Anagram program in C with explanation


In this tutorial, you will learn how to write a program in the C to check the given strings are Anagram or not.

The Complete logic behind it is :

  • To check given strings are anagram or not for that purpose we have to match each character of the string.
  • And also we have to count the occurrence of each characters from both the strings.
  • To implement it first we will arrange both strings in the same order.
  • And then compare each character of both string position wise.
  • If all positions have the same character in both strings then it means strings are anagram otherwise it is not an anagram.

Now before moving on writing the program first you should also know

Two strings can be called Anagram if the same character with the same occurrence, present in both string. In this case position of characters not matters.

For eg:  “quescol” and “colsque” both strings are anagram. As you can see here, both the string have same character with same time of occurrence at different position and it is an anagram.

But if we take another example like “love” and “like”. In the both string only two character ‘l’ and ‘e’ are common and rest are not. So this two strings are not an anagram.

How our program will behave?

This Program will take two String as an input. And after the comparison it will return output as Strings are anagram or not.

If the string is anagram then it will return “Given Strings are anagram” as an output.

And if Strings are not anagram then it will return “Strings are not anagram”.

Anagram program in c

#include <stdio.h>
#include <string.h>
#include <conio.h> 
int main()
  	char str1[100], str2[100], ch,temp;
  	int i, len1,len2, j;
  	printf("Please Enter first String :  ");
  	printf("Please Enter second String :  ");
	len1 = strlen(str1);
	len2 = strlen(str2); 
	 if(len1 != len2){
	    printf("given strings are not anagram");
	 for (i = 0; i < len1-1; i++) {
      for (j = i+1; j < len1; j++) {
         if (str1[i] > str1[j]) {
            temp  = str1[i];
            str1[i] = str1[j];
            str1[j] = temp;
         if (str2[i] > str2[j]) {
            temp  = str2[i];
            str2[i] = str2[j];
            str2[j] = temp;
	for(i = 0; i<len1; i++) {
      if(str1[i] != str2[i]) {    
         printf("Strings are not anagram \n", str1, str2);
         return 0;
  	printf("Given Strings are anagram \n");


anagram program in c

Explanation of the Anagram C program

  • Above program is to check given two strings are anagram or not.
  • All logic is written in the main() method.
  • We have 4 char variables str1, str2, ch and temp. str1 and str2 is array of character.
  • We have also integer variable i, len1, len2 and j.
  • Here the logic is very simple. We are taking here two strings as an input and then arranging it in ascending order .
  • Now then we are comparing both strings character, positions wise.
  • As string are a combination of characters. And each character are stored at array index.
  • It both strings are same then it will return output as “Strings are anagram”.
  • And if strings are not equal then it will return “Given Strings are not anagram”.

This was the all logic behind checking the given two strings are anagram or not.

I would recommend go through this program once again if any doubt.


It will help you to understand it.

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