Sum The Digits Of a Number Using Recursion in java

Java program to sum the digits of a number using recursion

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In this tutorial you will learn how to write a program in Java to sum the digits of a number using recursion.

Basically out agenda is to add the all digits of any number. So we will build our logic of the program accordingly.

If someone will give input 1547 then our program should give output after adding 1, 5, 4, and 7.

1+5+4+7 = 17.

So our program should print output as 17.

Also Read This: C program to sum digits of number.

How this Java program will behave?

Our program should give the output after addition of all the digits of a given number.

if someone has given input of 143 then out program should give 8 as a output.

Program 1: Find sum of number digits using Java Recursion

import java.util.*;  
class Main{
    static int sum=0,rem;
    static int sumOfDigits(int num)
    {
            sum = sum + (num%10);
            rem = num/10;
            if(rem > 0)
            {
                sumOfDigits(rem);
            }
            return sum;
    }
    public static void main(String ...args){
        int result;
        Scanner sc= new Scanner(System.in);
        System.out.print("Enter number- ");  
        int originalNum= sc.nextInt();  
        result = Main.sumOfDigits(originalNum);
        System.out.println("Sum = "+result);
    }
}

Output:

Enter number- 32425
Sum = 16

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