# Armstrong number program in python with explanation

Welcome back, In this tutorial we are going to learn how to write a program in python to check a given input number is Armstrong or not?

So before moving directly on the writing program I will recommend you please first know :

## What is Armstrong Number?

• It is a number which is equal to the sum of cube of its digits.
• For eg: 153, 370 etc.

Lets see it practically by calculating it,

Suppose I am taking 153 for an example

First calculate the cube of its each digits

1^3 = (1*1*1) = 1

5^3 = (5*5*5) = 125

3^3= (3*3*3) = 27

1+125+27 = 153

It means 153 is an Armstrong number.

Ok, Then move on the program when you have cleared concept 🙂

## Program to check a number is Armstrong or not in python programming language

``````i=0
result=0
n = int(input("please give a number : "))
number1 = n
temp = n
while n!=0:
n = (n//10)
i=i+1;
while number1!=0:
n=number1%10
result=result+pow(n,i)
number1=number1//10
if temp==result:
print("number is armstrong")
else:
print("number is not armstrong") ``````

Output: 